# print diamond pattern in python

You were able to print out half of the diamond, but now you have to try to make a function that prints a specific number of spaces, then a specific number of stars. Pythonic way to create a long multi-line string. Has the Star Trek away team ever beamed down to a planet with significantly higher or lower gravity than Earth? In this sample, we are using Python 3.6 f-string feature, and a combination of the reversed(), and range() functions. When is a closeable question also a “very low quality” question? What is the difference between the dead_code and unused lints? As I said I'm new to Python, I haven't learned that method yet and only know some commands. All you have to do is to find out how many spaces and asterisks should be there on each line. This will be done until the lower triangle is made.

From row 1 to (n+1)/2, the number of spaces decreases as the number of stars increase. Depending on which (space or star) one uses, (I used space) convert it to absolute value.
Does Python have a string 'contains' substring method? We will analyze the coding concept using a 2D matrix. For example, height is entered as 7 or 9 below. Does Python have a ternary conditional operator? The above code produces the same diamond shape, as shown in the previous example. The number of columns will be (2 x No. It includes a working sample for help. @Ali R - this is a beginner's solution and it's easier than the one above. This method will yield odd number actual height. Now, when the matrix is made we will begin with i=0, i
Python program to print alphabetical pattern; Star(asterisk) pattern in Python; By the time you will be done reading this post, you will have enough knowledge to code a diamond shape in python. How do I merge two dictionaries in a single expression in Python (taking union of dictionaries)? So from 6 to n, the # of stars = ((n+1 - row number) * 2) - 1, while # of spaces before stars = row number - 5. Is there something wrong with my fictional lighthouse?

(A space is represented as "0" here.). Could a top ranked GM draw against Stockfish using drawish opening lines in classical chess?

I looked at the way you explained it and tried to come up with another method instead of having division, and following a strategy similar to the half diamond. So from 1 to 5, the # of stars = (row number * 2) - 1, while # of spaces before stars = 5 - row number. In this technique, we’ll use the Python string property to repeat itself by a number specified along with the multiplication symbol. You need to develop a program that takes a number and prints, using stars, a full diamond of the given length. of rows -1) as there will a definite pattern while printing triangle. Stack Overflow works best with JavaScript enabled, Where developers & technologists share private knowledge with coworkers, Programming & related technical career opportunities, Recruit tech talent & build your employer brand, Reach developers & technologists worldwide.

From this information, you should be able to make a program that looks like this. Another way to look at it is this way (below), but it is similar to the half diamond where n is for row 1 to the maximum asterisks, and not to the total number of rows. Can we finally know the difference between these words? Program desc: Python sample code to print Diamond pattern """ """ Function to print Diamond pattern """ def diamond_pattern(lines): star = 0 for line in range(1, lines + 1): # inner loop to print blank char for space in range (1, (lines - line) + 1): print(end = " ") # inner loop to print star symbol while star != (2 * line - 1): … Now, we’ll use the code which prints the diamond pattern with just one loop statement. How can I keep our cats from endangering my pregnant wife. I would like to print the following pattern in Python 3.5 (I'm new to coding): But I only know how to print the following using the code below, but not sure how to invert it to make it a complete diamond: Since the middle and largest row of stars has 9 stars, you should make n equal to 9. The curly brackets in the print statement look complicated, but they're actually simple once you learn them. We will print ‘*’ at the place where the condition  [(columns//2)-i <= j <= (columns//2) +i]  is satisfied and blank spaces at the rest of the spots. We have demonstrated multiple techniques to print diamond pattern in this post.

This will be done until the upper triangle is made. arose with such larks as were abroad at the moment, I cannot understand how to properly fry seafood. We will increment ‘i’ and then again the condition will be checked.

Never mind! Why do we have undocumented and unsupported functions in SQL Server? :), The logic is the following: Why do some companies choose to file for bankruptcy if it has cash to pay off its immediate debts? import copy n = 10 #input: size of diamon raw = [] lst = [] re_lst = [] for a in range(n+1): if a%2 != 0: val = (n - a) // 2 raw = ''.join(" "*val + "*"*(a) + " "*val) lst.append(raw) re_lst = copy.deepcopy(lst) lst.reverse() #print diamond for i in re_lst: print(i) for i in lst: print(i) print("\n") #print series of diamond for i in re_lst: print(i) for i in lst: print(i) The diamond pattern is nothing but two triangles merged with their bases in contact with each other. The diamond pattern is nothing but two triangles merged with their bases in contact with each other. This process in end will result in the making of diamond shape. This marks (0,0) in the matrix. Analyzing the diamond pattern. Again, we will set ‘i’ and ‘j’ to 0(zero) to begin with printing the upside-down triangle. Here is a solution base on height equals to top to the middle, or half of the height. Consider that every line you print is a combination of spaces and asterisks (in your example, first line is 4 spaces, 1 asterisk, second line is 3 spaces, 3 astersisks, etc). Why does my model produce too good to be true output? Our objective of this exercise is to produce a diamond shape like the one given below. Please read and evaluate them one by one. Why is “1000000000000000 in range(1000000000000001)” so fast in Python 3? Now from row (n+1)/2 + 1 to row 9, the number of spaces increase while the number of stars decrease. Example: Row 1 will have 1 star, row 2 will have 3 stars and similarly row 3 will have 5 stars. Please help us improve Stack Overflow. This time the condition that will be checked will be (i <= j <= columns-1 -i ) and if this is satisfied we will print ‘*’ else blank spaces will be printed.Print(” “) changes the line in python, it is specific to python as by default it changes line at every command.

site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. So what can you deduce? For example, height is entered as 4(7) or 5(9) below. Print(” “) changes the line in python, it is specific to python as by default it changes the line after every command. This implementation doesn't require splitting the diamond into two loops (upper and lower halves). Note that you can replace n with any odd number to create a perfect diamond of that many lines. This python program explains a step by step process to print Diamond pattern using the Python range function. if you want both upper part and down side to be same change the count += 2 to count += 1, Or using reverse method, first one is diamond, second one is series of diamond. your coworkers to find and share information. So try to develop a pattern with the number of spaces and stars in each row. Printing Simple Diamond Pattern in Python, https://stackoverflow.com/a/32613884/4779556, Making the most of your one-on-one with your manager or other leadership, Podcast 281: The story behind Stack Overflow in Russian. How do we decide when a small sample is statistically significant or not? Great way to look at it! CODING CONCEPT (IN PYTHON 3) We will follow the following steps to make the diamond pattern … Why does the manual for inner tube say max psi is 4.5?

Does anyone recognize this signature from Lord Rayleigh's "The Theory of Sound"? When the user enters an even number for height, the diamond will be slightly slanted.